Nattres Levels And Curves 2.3.1
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Descriptions for Nattres Levels and Curves 2.3.1
Name: Nattres Levels and Curves
Version: 2.3.1
Mac Platform: Intel
OS Version: OS X 10.8 or later
Requirements:
Torrent Download Apple, Mac OS, Apps, Software,Games Torrents. Home; macOs Apps. Audio; Blu-ray; Books; Business; Clipboard; Code editor; Converter; Design Assets.
– Final Cut Pro 7 and 10
– Motion 4 and 5
– Adobe After Effects CS5 – CC 2014
– Adobe Premiere Pro CS6 – CC 2014
– FxFactory
Includes: Serial
Web Site: http://www.nattressplugins.com/levels-and-curves/
Overview
Adjustments on a whole new level
Presets for color grading log footage, to ensure you get a fine degree of control with your curves.
On-screen GUI for intuitive adjustments.
The key to grading with curve controls is to ensure that the range of control is designed to work well with the linearity of source image.
Ranges designed for video or log images
Nattress Levels and Curves controls have special mapping for video or log images to ensure you get a fine degree of control with your curves.
Mapping for Cineon and digital camera log formats
Video based images are placed into a specially constructed film-log space which also gives you the benefit of film-like contrast handling
What’s New in Nattres Levels and Curves 2.3.1
- Release notes not available at the time of this post.
Related Posts:
Four solutions were found :
- n = 2
- n = -7
- n =(-5-√-71)/2=(-5-i√ 71 )/2= -2.5000-4.2131i
- n =(-5+√-71)/2=(-5+i√ 71 )/2= -2.5000+4.2131i
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
(n+1)*(n+2)*(n+3)*(n+4)-(360)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
Step 2 :
Equation at the end of step 2 :
Step 3 :
Equation at the end of step 3 :
Step 4 :
Polynomial Roots Calculator :
4.1 Find roots (zeroes) of : F(n) = n4+10n3+35n2+50n-336
Polynomial Roots Calculator is a set of methods aimed at finding values of n for which F(n)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers n which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -336.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,7 ,8 ,12 ,14 ,16 , etc
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | -360.00 | |
| -2 | 1 | -2.00 | -360.00 | |
| -3 | 1 | -3.00 | -360.00 | |
| -4 | 1 | -4.00 | -360.00 | |
| -6 | 1 | -6.00 | -240.00 | |
| -7 | 1 | -7.00 | 0.00 | n+7 |
| -8 | 1 | -8.00 | 480.00 | |
| -12 | 1 | -12.00 | 7560.00 | |
| -14 | 1 | -14.00 | 16800.00 | |
| -16 | 1 | -16.00 | 32400.00 | |
| 1 | 1 | 1.00 | -240.00 | |
| 2 | 1 | 2.00 | 0.00 | n-2 |
| 3 | 1 | 3.00 | 480.00 | |
| 4 | 1 | 4.00 | 1320.00 | |
| 6 | 1 | 6.00 | 4680.00 | |
| 7 | 1 | 7.00 | 7560.00 | |
| 8 | 1 | 8.00 | 11520.00 | |
| 12 | 1 | 12.00 | 43320.00 | |
| 14 | 1 | 14.00 | 73080.00 | |
| 16 | 1 | 16.00 | 115920.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
n4+10n3+35n2+50n-336
can be divided by 2 different polynomials,including by n-2
Polynomial Long Division :
4.2 Polynomial Long Division
Dividing : n4+10n3+35n2+50n-336
('Dividend')
By : n-2 ('Divisor')
| dividend | n4 | + | 10n3 | + | 35n2 | + | 50n | - | 336 |
| - divisor | * n3 | n4 | - | 2n3 | |||||
| remainder | 12n3 | + | 35n2 | + | 50n | - | 336 | ||
| - divisor | * 12n2 | 12n3 | - | 24n2 | |||||
| remainder | 59n2 | + | 50n | - | 336 | ||||
| - divisor | * 59n1 | 59n2 | - | 118n | |||||
| remainder | 168n | - | 336 | ||||||
| - divisor | * 168n0 | 168n | - | 336 | |||||
| remainder | 0 |
Quotient : n3+12n2+59n+168 Remainder: 0
Polynomial Roots Calculator :
4.3 Find roots (zeroes) of : F(n) = n3+12n2+59n+168
See theory in step 4.1
In this case, the Leading Coefficient is 1 and the Trailing Constant is 168.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,7 ,8 ,12 ,14 ,21 , etc
Let us test ....
Mattress Levels And Curves 2.3.1 For Anet
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 120.00 | |
| -2 | 1 | -2.00 | 90.00 | |
| -3 | 1 | -3.00 | 72.00 | |
| -4 | 1 | -4.00 | 60.00 | |
| -6 | 1 | -6.00 | 30.00 | |
| -7 | 1 | -7.00 | 0.00 | n+7 |
| -8 | 1 | -8.00 | -48.00 | |
| -12 | 1 | -12.00 | -540.00 | |
| -14 | 1 | -14.00 | -1050.00 | |
| -21 | 1 | -21.00 | -5040.00 | |
| 1 | 1 | 1.00 | 240.00 | |
| 2 | 1 | 2.00 | 342.00 | |
| 3 | 1 | 3.00 | 480.00 | |
| 4 | 1 | 4.00 | 660.00 | |
| 6 | 1 | 6.00 | 1170.00 | |
| 7 | 1 | 7.00 | 1512.00 | |
| 8 | 1 | 8.00 | 1920.00 | |
| 12 | 1 | 12.00 | 4332.00 | |
| 14 | 1 | 14.00 | 6090.00 | |
| 21 | 1 | 21.00 | 15960.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
n3+12n2+59n+168
can be divided with n+7
Polynomial Long Division :
4.4 Polynomial Long Division
Dividing : n3+12n2+59n+168
('Dividend')
By : n+7 ('Divisor')
| dividend | n3 | + | 12n2 | + | 59n | + | 168 |
| - divisor | * n2 | n3 | + | 7n2 | |||
| remainder | 5n2 | + | 59n | + | 168 | ||
| - divisor | * 5n1 | 5n2 | + | 35n | |||
| remainder | 24n | + | 168 | ||||
| - divisor | * 24n0 | 24n | + | 168 | |||
| remainder | 0 |
Quotient : n2+5n+24 Remainder: 0
Trying to factor by splitting the middle term
4.5 Factoring n2+5n+24
The first term is, n2 its coefficient is 1.
The middle term is, +5n its coefficient is 5.
The last term, 'the constant', is +24
Step-1 : Multiply the coefficient of the first term by the constant 1 • 24 = 24
Step-2 : Find two factors of 24 whose sum equals the coefficient of the middle term, which is 5.
| -24 | + | -1 | = | -25 |
| -12 | + | -2 | = | -14 |
| -8 | + | -3 | = | -11 |
| -6 | + | -4 | = | -10 |
| -4 | + | -6 | = | -10 |
| -3 | + | -8 | = | -11 |
| -2 | + | -12 | = | -14 |
| -1 | + | -24 | = | -25 |
| 1 | + | 24 | = | 25 |
| 2 | + | 12 | = | 14 |
| 3 | + | 8 | = | 11 |
| 4 | + | 6 | = | 10 |
| 6 | + | 4 | = | 10 |
| 8 | + | 3 | = | 11 |
| 12 | + | 2 | = | 14 |
| 24 | + | 1 | = | 25 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 4 :
Step 5 :
Theory - Roots of a product :
5.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Parabola, Finding the Vertex :
5.2 Find the Vertex of y = n2+5n+24
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting 'y' because the coefficient of the first term, 1 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,An2+Bn+C,the n -coordinate of the vertex is given by -B/(2A) . In our case the n coordinate is -2.5000
Plugging into the parabola formula -2.5000 for n we can calculate the y -coordinate :
y = 1.0 * -2.50 * -2.50 + 5.0 * -2.50 + 24.0
or y = 17.750
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = n2+5n+24
Axis of Symmetry (dashed) {n}={-2.50}
Vertex at {n,y} = {-2.50,17.75}
Function has no real roots
Solve Quadratic Equation by Completing The Square
5.3 Solving n2+5n+24 = 0 by Completing The Square .
Subtract 24 from both side of the equation :
n2+5n = -24
Now the clever bit: Take the coefficient of n , which is 5 , divide by two, giving 5/2 , and finally square it giving 25/4
Add 25/4 to both sides of the equation :
On the right hand side we have :
-24 + 25/4 or, (-24/1)+(25/4)
The common denominator of the two fractions is 4 Adding (-96/4)+(25/4) gives -71/4
So adding to both sides we finally get :
n2+5n+(25/4) = -71/4
Adding 25/4 has completed the left hand side into a perfect square :
n2+5n+(25/4) =
(n+(5/2)) • (n+(5/2)) =
(n+(5/2))2
Things which are equal to the same thing are also equal to one another. Since
n2+5n+(25/4) = -71/4 and
n2+5n+(25/4) = (n+(5/2))2
then, according to the law of transitivity,
(n+(5/2))2 = -71/4
We'll refer to this Equation as Eq. #5.3.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(n+(5/2))2 is
(n+(5/2))2/2 =
(n+(5/2))1 =
n+(5/2)
Now, applying the Square Root Principle to Eq. #5.3.1 we get:
n+(5/2) = √ -71/4
Subtract 5/2 from both sides to obtain:
n = -5/2 + √ -71/4
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square roots of -1
Since a square root has two values, one positive and the other negative
n2 + 5n + 24 = 0
has two solutions:
n = -5/2 + √ 71/4 • i
or
n = -5/2 - √ 71/4 • i
Note that √ 71/4 can be written as
√ 71 / √ 4 which is √ 71 / 2
Solve Quadratic Equation using the Quadratic Formula
5.4 Solving n2+5n+24 = 0 by the Quadratic Formula .
According to the Quadratic Formula, n , the solution for An2+Bn+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
n = ————————
2A
In our case, A = 1
B = 5
C = 24
Accordingly, B2 - 4AC =
25 - 96 =
-71
Applying the quadratic formula :
-5 ± √ -71
n = ——————
2
In the set of real numbers, negative numbers do not have square roots. A new set of numbers, called complex, was invented so that negative numbers would have a square root. These numbers are written (a+b*i)
Both i and -i are the square roots of minus 1
Accordingly,√ -71 =
√ 71 • (-1) =
√ 71 • √ -1 =
± √ 71 • i
√ 71 , rounded to 4 decimal digits, is 8.4261
So now we are looking at:
n = ( -5 ± 8.426 i ) / 2
Two imaginary solutions :
Solving a Single Variable Equation :
5.5 Solve : n+7 = 0
Subtract 7 from both sides of the equation :
n = -7
Mattress Levels And Curves 2.3.1 Online
Solving a Single Variable Equation :
5.6 Solve : n-2 = 0
Add 2 to both sides of the equation :
n = 2
Four solutions were found :
- n = 2
- n = -7
- n =(-5-√-71)/2=(-5-i√ 71 )/2= -2.5000-4.2131i
- n =(-5+√-71)/2=(-5+i√ 71 )/2= -2.5000+4.2131i
Mattress Levels And Curves 2.3.1 Reviews
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